Zadanie 2d, Paper 1B, specimen 2025, Chemia IB SL

5 pktobliczenioweśrednie (szac.)Paper 1B, specimen 2025

Wzorowane na: Chemistry SL Paper 1B, specimen 2025, pytanie 2(d). Treść, dane i kontekst są zmienione; sprawdzane umiejętności, format i punktacja jak w oryginale.

Darmowe konto pozwoli wrócić do niego później.

Zadanie

Wspólne informacje do wiązki zadań

A student investigates how contact with air affects the iron(II) concentration of an iron(II) sulfate solution prepared as a lawn treatment. The solution is divided into equal portions in identical stoppered flasks, which are kept in a dark cupboard at room temperature for three weeks. Every day the stopper of each flask is taken out for a set number of hours, different for each flask, as shown.

five identical conical flasks containing equal volumes of solution, labelled 0 h, 2 h, 4 h, 12 h and 24 h; the first four are closed with stoppers, the 24 h flask is openPowiększ
five identical conical flasks containing equal volumes of solution, labelled 0 h, 2 h, 4 h, 12 h and 24 h; the first four are closed with stoppers, the 24 h flask is open

Polecenie

The student's results are shown in the graph.

line graph of iron(II) concentration in 10^-3 mol dm^-3 (0 to 7) against time in days (0 to 21) for the five flasks with daily exposure 0 h, 2 h, 4 h, 12 h and 24 hPowiększ
line graph of iron(II) concentration in 10^-3 mol dm^-3 (0 to 7) against time in days (0 to 21) for the five flasks with daily exposure 0 h, 2 h, 4 h, 12 h and 24 h

(i) Calculate the average rate at which the iron(II) concentration fell in the 24 h flask during the 21 days. Include units.

(ii) Before starting, the student proposed the hypothesis: "The longer a solution is left open to the air each day, the less iron(II) it will contain, because oxygen in the air oxidizes iron(II)."

Discuss whether the results support this hypothesis.

(iii) State what the results imply about how the iron(II) solution should be stored so that it stays effective.

Korepetytor AI

Nie wiesz, jak ruszyć? Korepetytor zna to zadanie i poprowadzi Cię krok po kroku, bez gotowca.

Wypróbuj za darmo

3 rozmowy · bez karty · Zaloguj się

Sprawdź się

Odpowiedz i oceń, jak poszło. Klucz odsłoń dopiero, gdy masz swoją odpowiedź.

Zanim porównasz z kluczem

Jak poszło Ci z tym zadaniem?

Zaloguj się, żeby zapisać ocenę i wrócić do zadania później.

Pokaż rozwiązanieUkryj rozwiązanieKlucz i punktacja

Odpowiedź z klucza

(i) «(6.2 × 10⁻³ mol dm−3 − 1.4 × 10⁻³ mol dm−3) / 21 d =» 2.3 × 10⁻⁴ ✔

mol dm−3 d−1 ✔

(ii) «supports» longer daily exposure gives a lower iron(II) concentration

OR

the 0 h flask decreases the least ✔

«does not fully support» no direct evidence that oxygen is the oxidizing agent «another component of the air, or something else, could be responsible» ✔

(iii) store in a sealed/full container «with little air above the solution» ✔

OR

use within a few days of opening ✔

Schemat punktowania

(i) M1: value in the range 2.2 × 10⁻⁴ to 2.4 × 10⁻⁴; M2: units mol dm⁻³ d⁻¹. Accept values converted to other units, such as 2.5 × 10⁻⁹ to 2.8 × 10⁻⁹ mol dm⁻³ s⁻¹ or 0.22 to 0.24 mmol dm⁻³ d⁻¹. (ii) [1] for evidence from the data that supports the trend, [1] for recognizing that the data do not identify oxygen as the cause. (iii) [1] for one valid storage implication.

Komentarz. Read both concentrations from the 24 h series and divide by 21 d, not by the number of readings. In (ii) both sides of the discussion are needed for full marks.

Umiejętności w zadaniu

Pliki cookies

Zapisujemy na Twoim urządzeniu to, bez czego serwis nie działa, np. zalogowanie. Plików analitycznych użyjemy tylko za Twoją zgodą. Szczegóły w polityce prywatności.