Zadanie 31, Paper 1A, maj 2025, TZ1, Chemia IB HL

The reaction between sodium thiosulfate and hydrochloric acid was carried out at several temperatures to determine its activation energy. A graph of ln k against $\dfrac{1}{T}$ was plotted from the processed data, and the gradient of the line of best fit was −9200 K.

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Which expression yields the activation energy, in kJ mol⁻¹, from this gradient?

$\ln k = -\dfrac{E_\mathrm{a}}{RT} + \ln A$

• A$\dfrac{-9200 \times R}{1000}\ \mathrm{kJ\,mol^{-1}}$Zapytaj
• B$\dfrac{9200 \times 1000}{R}\ \mathrm{kJ\,mol^{-1}}$Zapytaj
• C$\dfrac{9200 \times R}{1000}\ \mathrm{kJ\,mol^{-1}}$Zapytaj
• D$\dfrac{-9200 \times 1000}{R}\ \mathrm{kJ\,mol^{-1}}$Zapytaj