Zadanie 7, Paper 2, maj 2022, TZ1, Biologia IB SL
Wzorowane na: Biology SL Paper 2, May 2022, TZ1, pytanie 7. Treść, dane i kontekst są zmienione; sprawdzane umiejętności, format i punktacja jak w oryginale.
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Zadanie
Polecenie
Inheritance and cell division contribute to biological variation.
(a) Draw and label one RNA nucleotide.
(b) Distinguish mitosis from meiosis.
(c) Explain how natural selection can produce antibiotic resistance in a bacterial population.
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Pokaż rozwiązanieUkryj rozwiązanieKlucz i punktacja
Odpowiedź z klucza
(a) Ribose drawn as a pentagon and labelled. ✔
A labelled nitrogenous base joined to the 1′ position of ribose. ✔
A labelled phosphate group joined through the 5′ position. ✔
(b) In animals, mitosis produces somatic cells whereas meiosis produces cells of the sexual reproductive pathway. ✔
Mitosis has one division, meiosis two. ✔
Mitosis usually yields two daughter cells, meiosis four products. ✔
Mitosis generally preserves genetic identity, whereas meiosis generates variation. ✔
Mitosis supports growth and repair; meiosis supports sexual reproduction. ✔
Mitosis preserves chromosome number; meiosis halves it. ✔
Homologous chromosomes pair in meiosis but not ordinary mitosis. ✔
Crossing over is characteristic of meiosis, not ordinary mitosis. ✔
(c) An antibiotic kills or inhibits susceptible bacteria. ✔
Resistance varies among bacteria. ✔
Random mutation can generate resistance. ✔
Resistant bacteria are not killed by the antibiotic OR susceptible bacteria are killed. ✔
This gives a selective advantage or unequal reproductive success. ✔
Surviving resistant bacteria reproduce. ✔
The resistance allele is inherited by their descendants. ✔
Resistant variants become more frequent. ✔
The population has evolved increased resistance. ✔
Quality: the response is clear on first reading, concise and contains little repetition or irrelevant material. ✔
Schemat punktowania
Part (a):1 per correctly drawn and labelled feature,maximum 3; if more than one nucleotide is drawn,maximum 2. “Sugar” without ribose is insufficient. Part (b):any 5 paired contrasts,maximum 5; no credit for unpaired statements. Part (c):any 7 points,maximum 7; cap at 6 if “pathogen” is used throughout without identifying bacteria. Award 1 independent communication-quality mark. Total 16.
Umiejętności w zadaniu
- Genetic diversity generated by meiosisĆwicz podobne
- Inheritance as a requirement for selection responseĆwicz podobne
- Parts of a nucleotideĆwicz podobne
- Selective effects of antibioticsĆwicz podobne
- Selection for antibiotic-resistant bacteriaĆwicz podobne
- Relative fitness and reproductive successĆwicz podobne
- Purposes of mitotic and meiotic nuclear divisionĆwicz podobne
- Halving chromosome number through meiosisĆwicz podobne