Zadanie 4
What is the number of hydrogen atoms in 0.200 mol of propylamine, C3H7NH2? NA = 6.02 × 1023 mol−1 A. 1.20 × 1023 B. 1.08 × 1024 C. 8.43 × 1023 D. 1.08 × 1025
Define the mole as the SI unit of amount of substance, use the Avogadro constant (6.02 × 10²³ mol⁻¹) to convert between moles and numbers of atoms, molecules, ions or electrons, and count particles inside a formula (oxygen atoms in 2 mol of H2SO4).
Tę umiejętność sprawdza 10 zadań wzorowanych na arkuszach IB z lat 2022–2026.
What is the number of hydrogen atoms in 0.200 mol of propylamine, C3H7NH2? NA = 6.02 × 1023 mol−1 A. 1.20 × 1023 B. 1.08 × 1024 C. 8.43 × 1023 D. 1.08 × 1025
How many ions are present in 142 g of Na2SO4? M(Na2SO4) = 142 g mol−1 A. 1 B. 3 C. 6.02 × 1023 D. 1.81 × 1024
What is the number of hydrogen atoms in 0.0500 mol of hydrated magnesium sulfate, MgSO4 ⋅ 7 H2O? A. 3.01 × 1022 B. 4.21 × 1023 C. 2.11 × 1023 D. 4.21 × 1022
A total charge of 1500.0 C flows through the external circuit during one discharge of the battery. Determine how many sodium ions are released at the anode. Use section 2 of the data booklet.
4.81 g of sulfur was heated in a stream of chlorine gas until the reaction was complete. The mass of the chloride produced was 10.13 g. (i) Calculate how many atoms are present in this 4.81 g sample of sulfur. Use sections 2 and 7 of the data booklet. (ii)…
What is the total number of ions in 0.30 mol of iron(III) nitrate, Fe(NO3)3? A. 0.30 × 1 × 6.02 × 1023 B. 0.30 × 3 × 6.02 × 1023 C. 0.30 × 4 × 6.02 × 1023 D.…
A cylinder contains 80 g of argon and 12.0 g of helium. What is the ratio of the number of argon atoms to the number of helium atoms in the cylinder? A. 0.15 B. 0.67 C. 1.5 D. 6.7
What is the mass of one molecule of white phosphorus, P4? Use NA = 6.02 × 1023 mol−1. A. 5.1 × 10−23 g B. 2.1 × 10−22 g C. 4.9 × 1021 g D. 7.5 × 1025 g
Iron has a number of natural isotopes. A sample of iron was enriched in to produce a mixture with the following composition: (i) Calculate the relative atomic mass of the enriched sample, giving your answer to two decimal places. (ii) Natural…
How many oxygen atoms are present in 0.0200 mol of aluminium sulfate, Al2(SO4)3? NA = 6.02 × 1023 mol−1 A. 1.20 × 1022 B. 4.82 × 1022 C. 1.44 × 1023 D. 1.44 × 1024
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