Zadanie 6a
Wzorowane na: Chemistry HL Paper 2, May 2026, TZ2, pytanie 6(a). Treść, dane i kontekst są zmienione; sprawdzane umiejętności, format i punktacja jak w oryginale.
Darmowe konto pozwoli wrócić do niego później.
Informacja do zadań 6a-6c.
Nitrogen(II) oxide reacts with chlorine in the gas phase at constant temperature.
2 NO(g) + Cl2(g) → 2 NOCl(g)
Initial rates of reaction were measured using different initial concentrations of the reactants.
| [NO] / mol dm−3 | [Cl2] / mol dm−3 | Initial rate / mol dm−3 s−1 |
|---|---|---|
| 1.0 × 10−2 | 4.0 × 10−3 | 8.0 × 10−5 |
| 2.0 × 10−2 | 4.0 × 10−3 | 3.2 × 10−4 |
| 2.0 × 10−2 | 2.0 × 10−3 | 1.6 × 10−4 |
Polecenie
Deduce the order of reaction with respect to NO and with respect to Cl2, and write the rate equation.
Sprawdź rozwiązanieUkryj rozwiązanieKlucz CKE i punktacja
Odpowiedź z klucza
Order of reaction with respect to NO: 2 ✔ «doubling [NO] at constant [Cl2] multiplies the rate by 4»
AND
Order of reaction with respect to Cl2: 1 ✔ «halving [Cl2] at constant [NO] halves the rate»
Rate equation: «rate =» k[NO]2[Cl2] ✔
Schemat punktowania
[2] M1 both orders correct; M2 rate equation consistent with the orders given; ECF from M1. Do not deduce the orders from the coefficients of the equation.
Komentarz
Here the orders happen to equal the coefficients in the equation, but they must be shown from the table: doubling [NO] quadruples the rate and halving [Cl2] halves it.