Zadanie 1b

6 pktotwarteśrednie (szac.)Paper 2, maj 2026, TZ2

Wzorowane na: Chemistry HL Paper 2, May 2026, TZ2, pytanie 1(b). Treść, dane i kontekst są zmienione; sprawdzane umiejętności, format i punktacja jak w oryginale.

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Polecenie

Sulfapyridine is an antibacterial drug. Its structure is shown below.

structural formula of the drug molecule

C11H11N3O2S

Mr = 249.32

(i) Deduce the hybridization of the nitrogen atom that is part of a ring.

(ii) Describe how the sigma (σ) and pi (π) components of an S=O bond in sulfapyridine are formed.

(iii) Deduce how many signals appear in the 1H NMR spectrum of sulfapyridine and the relative areas of those signals.

(iv) Calculate the mass percentage of nitrogen in sulfapyridine. Use section 7 of the data booklet.

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Odpowiedź z klucza

(i) sp2 ✔ «three electron domains on the ring nitrogen: two sigma bonds to carbon atoms and a lone pair; the fourth orbital is an unhybridized p orbital in the pi system»

(ii) sigma (σ) bond: head-on overlap / combination of atomic orbitals «of S and O, along the bond axis» ✔

pi (π) bond: lateral / sideways overlap / combination of p orbitals «of S and O» ✔

(iii) Number of signals: 8 ✔

Relative areas: 2 : 2 : 2 : 1 : 1 : 1 : 1 : 1 «two kinds of benzene ring H, 2 H each; NH2, 2 H; NH, 1 H; four different ring H on the pyridine ring, 1 H each; in any order» ✔

(iv) «3×14.01×100249.32=\dfrac{3 \times 14.01 \times 100}{249.32} =» 16.86 «%» ✔

Schemat punktowania

(i) [1] sp2. (ii) [2] M1 sigma bond: head-on overlap of orbitals; M2 pi bond: sideways overlap of p orbitals; accept suitable diagrams. (iii) [2] M1 eight signals; M2 relative areas, accepted in any order. (iv) [1] 16.86 %; accept 16.9 %.

Komentarz

In (iii) the hydrogen atoms on nitrogen give signals of their own, so NH2 and NH are counted separately, and the four hydrogens on the pyridine ring are all in different environments.

Umiejętności w zadaniu