Describe sigma bonds as head-on overlap of orbitals along the bond axis and pi bonds as side-on overlap of p orbitals above and below the axis, and count the sigma and pi bonds in a molecule or ion from its structure.
Tę umiejętność sprawdza 14 zadań wzorowanych na arkuszach IB z lat 2022–2026.
Chemia IBPaper 2, maj 2026, TZ2wzorowane6 pktotwarteśrednie (szac.)
Sulfapyridine is an antibacterial drug. Its structure is shown below. C11H11N3O2S Mr = 249.32 (i) Deduce the hybridization of the nitrogen atom that is part of a ring. (ii) Describe how the sigma (σ) and pi (π) components of an…
Chemia IBPaper 1A, maj 2026, TZ3wzorowane1 pktzamknięteśrednie (szac.)
Asparagine, an amino acid, has the structure shown. What are the numbers of sigma (σ) and pi (π) bonds in one molecule of asparagine? A. 14 σ and 2 π B. 16 σ and 4 π C. 16 σ and 2 π D. 18 σ and 2 π
Chemia IBPaper 1A, maj 2026, TZ1wzorowane1 pktzamknięteśrednie (szac.)
How many sigma and pi bonds are present in pent-1-yne, C5H8? A. 12 sigma bonds and 2 pi bonds B. 8 sigma bonds and 3 pi bonds C. 13 sigma bonds and 1 pi bond D. 9 sigma bonds and 4 pi bonds
Chemia IBPaper 1A, maj 2026, TZ2wzorowane1 pktzamknięteśrednie (szac.)
How many sigma bonds and pi bonds are in a molecule of the fatty acid shown, C12H20O2? In each option the number of sigma bonds is given first and the number of pi bonds second. A. 13 sigma, 3 pi B. 33 sigma, 6 pi C. 33 sigma, 3 pi D. 36 sigma, 3 pi
Chemia IBPaper 1A, listopad 2025, TZ1wzorowane1 pktzamknięteśrednie (szac.)
Which orbitals overlap to form the σ-bond and the two π-bonds between carbon and nitrogen in hydrogen cyanide, HCN? A. σ-bond: sp and sp3; π-bonds: p and p B. σ-bond: sp and sp; π-bonds: p and p C. σ-bond: sp…
Chemia IBPaper 1A, listopad 2025, TZ3wzorowane1 pktzamkniętełatwe (szac.)
What are the numbers of σ (sigma) and π (pi) bonds in one molecule of prop-2-ynal, HC≡CCHO? A. 5 σ and 3 π B. 3 σ and 3 π C. 3 σ and 5 π D. 6 σ and 2 π
Chemia IBPaper 1A, specimen 2025wzorowane1 pktzamknięteśrednie (szac.)
Which pair of statements about the electrons in this molecule is correct? A. 3 non-bonding pairs of electrons and 8 electrons in π bonds B. 5 non-bonding pairs of electrons and 8 electrons in π bonds C. 5 non-bonding pairs of electrons and 10 electrons…
Chemia IBPaper 1, maj 2024, TZ2wzorowane1 pktzamknięteśrednie (szac.)
What are the numbers of sigma and pi bonds in a molecule of propenenitrile, CH2=CH−C≡N? A. 6 sigma bonds and 3 pi bonds B. 7 sigma bonds and 3 pi bonds C. 6 sigma bonds and 2 pi bonds D. 9 sigma bonds and no pi bonds
Chemia IBPaper 2, listopad 2024wzorowane3 pktotwartełatwe (szac.)
2-Methylbut-1-ene contains sigma (σ) and pi (π) bonds. (i) State the hybridization of carbon atoms A and B. (ii) Describe how the sigma bond and the pi bond of the carbon-carbon double bond in 2-methylbut-1-ene are formed.
Chemia IBPaper 1, listopad 2024wzorowane1 pktzamknięteśrednie (szac.)
How many sigma (σ) bonds and how many pi (π) bonds does one molecule of the compound below contain? HC≡C−CH=CH−C≡N A. 5 σ and 8 π B. 8 σ and 5 π C. 9 σ and 5 π D. 13 σ and 5 π
Chemia IBPaper 2, maj 2023, TZ2wzorowane3 pktotwarteśrednie (szac.)
Describe, in terms of the orbitals involved, the bonding between carbon atoms 1 and 2 in pent-1-ene.
Chemia IBPaper 2, maj 2022, TZ1wzorowane5 pktotwarteśrednie (szac.)
(i) State the IUPAC name of Compound B. (ii) Both compounds are liquids at room temperature. Identify the strongest intermolecular force between molecules of Compound B. (iii) State how many σ (sigma) bonds and how many π (pi) bonds one molecule of Compound A…
Chemia IBPaper 2, maj 2022, TZ2wzorowane4 pktotwarteśrednie (szac.)
(i) Sketch the shape of a sigma (σ) bond and of a pi (π) bond, showing the overlapping orbitals. Sigma (σ): Pi (π): (ii) Identify the number of sigma bonds and the number of pi bonds in one molecule of acrylonitrile. Sigma (σ): Pi (π): (iii) State the…
Chemia IBPaper 1, maj 2022, TZ1wzorowane1 pktzamknięteśrednie (szac.)
In which compound are all the carbon atoms sp2 hybridized? A. Buta-1,3-diene, CH2=CH−CH=CH2 B. Propene, CH2=CH−CH3 C. Propadiene, CH2=C=CH2 D. But-2-yne, CH3−C≡C−CH3