Zadanie 2c
Wzorowane na: Chemistry HL Paper 2, May 2026, TZ3, pytanie 2(c). Treść, dane i kontekst są zmienione; sprawdzane umiejętności, format i punktacja jak w oryginale.
Darmowe konto pozwoli wrócić do niego później.
Informacja do zadań 2a-2c.
Sulfur dioxide, SO2, is a covalently bonded compound and a common air pollutant released when sulfur-containing fuels burn.
Polecenie
Nitrogen monoxide reacts with chlorine in the atmosphere:
2 NO(g) + Cl2(g) → 2 NOCl(g)
The rate equation was determined experimentally as Rate = k[NO]2[Cl2].
(i) A student proposed the following mechanism and suggested that Step 1 was the rate-determining step.
Step 1: NO(g) + Cl2(g) → NOCl2(g)
Step 2: NOCl2(g) + NO(g) → 2 NOCl(g)
Evaluate the proposed mechanism and the rate-determining step.
(ii) Calculate the value and the units of the rate constant, k, using these data from one experiment.
| [NO] / mol dm−3 | [Cl2] / mol dm−3 | Rate / mol dm−3 s−1 |
|---|---|---|
| 2.5 × 10−2 | 1.8 × 10−2 | 4.5 × 10−5 |
Sprawdź rozwiązanieUkryj rozwiązanieKlucz CKE i punktacja
Odpowiedź z klucza
(i) the two steps add up to the overall equation 2 NO + Cl2 → 2 NOCl «NOCl2 is an intermediate», so the mechanism is consistent with the stoichiometry ✔
Step 1 cannot be the rate-determining step, because it would give Rate = k[NO][Cl2], first order in NO «not second order»;
Step 2 is the rate-determining step «with Step 1 a fast equilibrium», which gives Rate = k[NO]2[Cl2] ✔
(ii) «» 4.0 ✔
mol−2 dm6 s−1 ✔
Schemat punktowania
(i) M1: the steps sum to the overall equation, so the mechanism is consistent with the stoichiometry; M2: Step 1 is rejected as the rate-determining step because it would give a rate equation first order in NO, AND Step 2 is identified as the slow step (accept "Step 1 is a fast equilibrium"). Do not award M2 for the bare statement that the student is wrong. (ii) Award [2] for the correct value with correct units; [1] for the value and [1] for the units.
Komentarz
The intermediate NOCl2 forms from one NO and one Cl2, and Step 2 adds the second NO, so a slow Step 2 after a fast Step 1 reproduces the experimental rate equation.