Zadanie 1d, Paper 2, maj 2025, TZ1, Chemia IB HL

«IE(Sn) = 709 kJ mol⁻¹»

E for one atom «$= \dfrac{709 \times 10^{3}\ \mathrm{J\,mol^{-1}}}{6.02 \times 10^{23}\ \mathrm{mol^{-1}}}$» = 1.18 × 10⁻¹⁸ «J» ✔

f «$= \dfrac{E}{h} = \dfrac{1.18 \times 10^{-18}\ \mathrm{J}}{6.63 \times 10^{-34}\ \mathrm{J\,s}}$» = 1.78 × 10¹⁵ «s⁻¹» ✔

λ «$= \dfrac{c}{f} = \dfrac{3.00 \times 10^{8}\ \mathrm{m\,s^{-1}}}{1.78 \times 10^{15}\ \mathrm{s^{-1}}}$» = 1.69 × 10⁻⁷ «m» ✔

M1: energy per atom from the first ionization energy of tin (709 kJ mol-1 converted to J and divided by the Avogadro constant); M2: frequency from E = hf; M3: wavelength from c = fλ. Award [3] for a correct final answer «1.69 × 10^-7 m». ECF from M1 and M2.