Percentage yield calculations

Calculate percentage yield as experimental yield divided by theoretical yield, and solve combined problems involving reacting quantities, limiting reactants and the mass of product actually obtained.

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Zadanie 4bPaper 2, maj 2025, TZ2
wzorowane2 pktobliczenioweśrednie (szac.)

A chemist treated 22.99 g of galantamine with sulfuric acid to make the sulfate salt: 2CX17HX21NOX3+HX2SOX4(CX17HX22NOX3)X2SOX4\ce{2C17H21NO3 + H2SO4 -> (C17H22NO3)2SO4} The mass of salt isolated was 24.65 g. Determine the percentage yield of the salt. Use section 7 of the data booklet.

Zadanie 21Paper 1A, listopad 2025, TZ1
wzorowane1 pktzamknięteśrednie (szac.)

Nitrogen gas is reacted with excess hydrogen gas to produce ammonia. NX2(g)+3HX2(g)2NHX3(g)\ce{N2(g) + 3H2(g) -> 2NH3(g)} The reaction of 28.0 g of NX2\ce{N2} with excess HX2\ce{H2} produces 25.5 g of NHX3\ce{NH3}. What is the percentage yield of NHX3\ce{NH3}? A. 25% B. 50% C. 75% D.…

Zadanie 19Paper 1A, specimen 2025
wzorowane1 pktzamknięteśrednie (szac.)

Ammonia is oxidized according to the equation below. 4NHX3(g)+5OX2(g)4NO(g)+6HX2O(g)\ce{4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)} What is the amount, in mol, of HX2O\ce{H2O} produced when 8.00 mol of NHX3\ce{NH3} reacts with 5.00 mol of OX2\ce{O2}, if the yield is 80 %? A. 4.80 B. 6.00 C. 9.60 D.…

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