Zadania z chemii IB SL

Znalezionych zadań: 16

Filtry i umiejętności2

The final step can be summarized as: $\ce{3NO2(g) + H2O(l) -> 2HNO3(aq) + NO(g)}$

\Delta H^\ominus = -138\ \mathrm{kJ\,mol^{-1}}

Describe the types of bonding found in the concentrated aqueous nitric acid product.

Nitric acid, $\ce{HNO3}$ , is strong, while nitrous acid, $\ce{HNO2}$ , is weak. (i) Outline the difference between a strong and a weak acid. (ii) Deduce the Lewis formula and the molecular geometry for the nitrite ion, $\ce{NO2-}$ .

(i) Write the equation for the reaction of Rb with water, $\ce{H2O}$ , including state symbols. (ii) Describe the type of bonding in $\ce{Rb}$ and in $\ce{H2O}$ , and explain how the valence electrons in each produce that type of bond.

What is the correct electron domain geometry and molecular geometry of $\ce{NCl3}$ ? A. Trigonal planar electron domain geometry, trigonal planar molecular geometry B. Tetrahedral electron domain geometry, trigonal pyramidal molecular geometry C. Trigonal…

At room temperature hydrogen cyanide is a liquid that evaporates readily, whereas ethyne, $\ce{C2H2}$ , which has almost the same molar mass, is a gas that boils at −84 °C. (i) Draw the Lewis formula of the hydrogen cyanide molecule, showing all valence…

Both ionic and covalent bonding are present in sodium ethanedioate, $\ce{Na2C2O4}$ . (i) Describe the two types of bonding. Ionic bonding: Covalent bonding: (ii) Deduce a Lewis formula of the ethanedioate ion, $\ce{C2O4^2-}$ . (iii) State the geometry of the…

(i) State the electron configuration of a nitrogen atom. (ii) Draw the Lewis formula of ammonia. (iii) Deduce the electron domain geometry and the molecular geometry of the ammonia molecule. (iv) Explain why the ammonia molecule is polar.

For which of these molecules is the octet rule satisfied by every atom? I. $\ce{SiCl4}$ II. $\ce{NCl3}$ III. $\ce{BCl3}$ A. I and II only B. I and III only C. II and III only D. I, II and III

Which row lists these molecules in order of increasing bond angle? A. $\ce{NF3}$ , $\ce{SiH4}$ , $\ce{HCHO}$ , $\ce{C2H2}$ B. $\ce{SiH4}$ , $\ce{NF3}$ , $\ce{HCHO}$ , $\ce{C2H2}$ C. $\ce{NF3}$ , $\ce{HCHO}$ , $\ce{SiH4}$ , $\ce{C2H2}$ D. $\ce{C2H2}$ , $\ce{HCHO}$ ,…

Simple bonding theory expects every atom in a covalent molecule to end up with eight valence electrons. Two stable gas-phase molecules, $\ce{BF3(g)}$ and $\ce{BeF2(g)}$ , do not fit this picture. Which adaptation of the bonding model was needed to explain…