Zadanie 1c

3 pktotwarteśrednie (szac.)Paper 3, maj 2024, TZ1

Wzorowane na: Chemistry SL Paper 3, May 2024, TZ1, pytanie 1(c). Treść, dane i kontekst są zmienione; sprawdzane umiejętności, format i punktacja jak w oryginale.

Darmowe konto pozwoli wrócić do niego później.

Informacja do zadań 1a-1c.

A laboratory investigation uses the oxygen released by aqueous hydrogen peroxide to follow its decomposition.

2 H2O2(aq) → 2 H2O(l) + O2(g)

For each run, a weighed portion of copper(II) oxide powder, CuO(s), is mixed with 30.0 cm3 of peroxide solution. A graduated gas syringe collects the oxygen. Readings taken at fixed time intervals give the five curves in Figure 1, each obtained with a different catalyst mass.

Figure 1: graph of oxygen volume against time for different catalyst masses

Polecenie

The results in Figure 1 were processed to give Figure 2, which shows how the initial rate of reaction varies with the mass of catalyst.

Figure 2: graph of initial reaction rate against catalyst mass

(i) Outline how the y-axis values in Figure 2 were obtained from the results in Figure 1.

(ii) Suggest, giving a reason, whether a best-fit line drawn through the points in Figure 2 should pass through the origin.

Sprawdź rozwiązanieUkryj rozwiązanieKlucz i punktacja

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Odpowiedź z klucza

(i) a tangent is drawn to each curve at t = 0 ✔

the gradient «of the tangent» is calculated «change in volume divided by change in time» ✔

(ii) yes AND the rate is «almost» zero when no catalyst is present

OR

no AND the decomposition still occurs, slowly, without a catalyst ✔

Schemat punktowania

M1: tangent at the start of the reaction (accept "at 0 s"); a line joining two points is not enough. M2: gradient calculation; do not accept "taking the derivative" alone. M3: either decision with its matching reason. Do not accept "yes, because the line fits the data better".

Umiejętności w zadaniu