Zadanie 1a
Take b=2,d=3. (i) Sketch y=f(x), labelling its axis intercepts. (ii) Hence explain why f(x)=0 has no real root.
Zadania wzorowane na pytaniach z tego arkusza: te same umiejętności, format i punktacja, inne dane i kontekst. Treści arkusza IB nie publikujemy.
W bazie 15 zadań z tego arkusza, razem 55 punktów, każde z kluczem i schematem punktowania.
Take b=2,d=3. (i) Sketch y=f(x), labelling its axis intercepts. (ii) Hence explain why f(x)=0 has no real root.
Take b=−2,d=1. Sketch y=f(x), labelling its axis intercepts.
For the general family, (i) find f′(x); (ii) prove that f′ is odd.
For a real double root α, describe the identifying feature of y=f(x) at x=α.
Prove that −α is also a double root.
(i) Using f′(α)=0 or otherwise, show that α4 = −b/2. (ii) Hence show that d = b2/4.
Under the double-root assumption, state the b-values for which f(x)=0 has (i) at least one real root; (ii) at least one purely imaginary root.
For b<0, show that the real zeros of f″ are 0 and .
Let . At the inflection point x=t, the tangent is y=mx+c, where m = (16b/7)t3. Show that c = d + 9b2/28.
For the test run, find (i) the amplitude; (ii) the initial displacement; (iii) the first positive time at which the head passes O.
Find ds/dt and d²s/dt² and thereby verify the restoring-acceleration equation.
(i) Use the chain rule to establish a = v dv/ds on a monotone motion branch. (ii) Solve the resulting differential equation to prove v2 = n2(A2 − s2). (iii) Hence or otherwise find the maximum speed.
Show that .
On the branch moving in the positive direction, write the positive velocity as v₊(s). For −A<s<A, the density has form fS(s) = k/v+(s) with k>0. Find k.
(i) Find E(S), with justification. (ii) Interpret this value in the scanning-head model.
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