Zadanie 1a
Take b=2,d=3. (i) Sketch y=f(x), labelling its axis intercepts. (ii) Hence explain why f(x)=0 has no real root.
Use factor and remainder arguments, root sums and products, and graph behaviour to analyse polynomial equations.
Tę umiejętność sprawdza 60 zadań wzorowanych na arkuszach IB z lat 2022–2026.
Take b=2,d=3. (i) Sketch y=f(x), labelling its axis intercepts. (ii) Hence explain why f(x)=0 has no real root.
Take b=−2,d=1. Sketch y=f(x), labelling its axis intercepts.
For a real double root α, describe the identifying feature of y=f(x) at x=α.
Prove that −α is also a double root.
(i) Using f′(α)=0 or otherwise, show that α4 = −b/2. (ii) Hence show that d = b2/4.
Under the double-root assumption, state the b-values for which f(x)=0 has (i) at least one real root; (ii) at least one purely imaginary root.
Find the other two roots.
Using sums and products of roots: (i) show that a=3; (ii) find b.
Express P as (Az + B)(z2 + Cz + D)(z2 + Ez + F) with integer coefficients.
First suppose is finite. (i) Show that b=2a−4. (ii) Find the limit in terms of a.
Verify that z²−9 is a factor of P(z).
The already-specified quadratic factor is z2 − 9. P is the product of three quadratic polynomials with real coefficients. Find the other two quadratic factors.
Let F(x) = 3x4 − 4x3 + px2 + qx + 1. The polynomial has factor x + 1, and division by x − 2 leaves remainder 45. Determine p and q.
Find the allowable values of k if the two solutions also have the same sign.
The polynomial F(x) = x4 + px3 − 2x2 + qx − 8 is divisible by (x − 2)2. Determine the real coefficients p and q.
These four roots obey . Their reciprocals obey , where p, q, r are integers with no common factor and p > 0. Find p, q, r.
The monic quartic is z4 + az3 + bz2 + cz + d = 0, with real coefficients. Two distinct roots z1, z2 satisfy the circle condition and . Find the coefficient a of this…
The normal to F at A is y = −t2x + kt3 − k/t. (i) Show that its intersections with F satisfy x2 − k(t − t−3)x − k2/t2 = 0. (ii) Hence, using a sum/product of roots or another valid method, find B.
Let P(x) = 3x2 + qx + r, with real coefficients and real roots α,β. Division by x+1 leaves remainder 14. Given α2 + β2 = 23/3, find q and r.
For F, show that .
For F, find the exact value of (xB − xA)/(xC − xB).
State α + β + γ.
Show that p=2.
It is further given that h(−1/3) = 0 and α, β are positive integers with α < β. (i) Show that αβ = 3. (ii) Find α and β.
Find the product of the solutions of f(x)=g(x).
Show that x−1 is a factor of P.
Hence express P as a product of three linear factors.
For p(x) = ax2 + bx + a, where a≠0, verify p(x) = x2p(1/x) for x≠0.
If α≠0 is a root of a palindromic polynomial p of degree n, prove that 1/α is also a root.
Prove that the product of two palindromic polynomials is palindromic.
Write F(x) = (x4 + ux2 + 1)(x4 + vx2 + 1), where u,v are integers with u<v. Determine u,v by forming and solving an appropriate system of equations.
Hence find all roots of F(x) = 0 exactly, stating multiplicities.
Prove that every monic palindromic polynomial of odd degree has −1 as a root.
For the cubic family, state (i)r1 + r2 and (ii)r1r2 in terms of a,b,c.
For an admissible cubic F: (i) express r2 − r1 in terms of a,b; (ii) use the sum and difference of the stationary abscissas to show that r1 = (3a2 − 3ab − 2b)/(6a); (iii) use this result to show that b=0 or a=−1/3.
Determine the two admissible cubic functions with b=0.
Now set a=−1/3. (i) Express r₁ in terms of b. (ii) Hence or otherwise find the exact pairs (b,c) making F admissible. Give each value as a rational expression involving a square root.
For m>0, let P(z) = 5m − mz + (20/m)z2 − z3. Given that z−2i is a factor, find every root of P(z)=0.
(i) Find the other roots of p(z)=0. (ii) By a suitable transformation or otherwise, solve 1+3w−6w²+20w³=0.
The inflexion point P lies in . Given y′′ = (−4x4 + 2x2y2 + 2y4)/(x2y3), use this expression to show that P lies on a line y=mx and determine m exactly.
Set a=−4. By varying b systematically or otherwise, find the two b values for which F has a repeated real root.
For a=−4, state the b values giving (i) no x-axis intercepts; (ii) four distinct x-axis intercepts.
Now set a=4. State the b values giving (i) exactly one intercept; (ii) no intercepts; (iii) exactly two intercepts.
Prove that a<0 and 0<b<a²/4 imply exactly four distinct x-axis intercepts.
A rational point has two rational coordinates. On C : y2 = x3 − 3x + 4, let P=(0,2). The tangent at P meets C again at Q; let S=(0,−2). (i) Find the tangent equation at P. (ii) Hence find Q, expressing its coordinates as fractions.
A rational point has two rational coordinates. On C : y2 = x3 − 3x + 4, let P=(0,2). The tangent at P meets C again at Q; let S=(0,−2). Use the tangent construction to determine Q, then find the third intersection of the full straight line through Q and S with C.
Let g(x) = (x − r)2[(x − a)2 + b2], b>0, with A=(a,g(a)) and R=(r,0). When a≠r the tangent at A has x-intercept T=((a+r)/2,0). Assume (a − r)2 > 2b2, so the quartic has two inflection points. (i) Show that their x-coordinates satisfy…
Expand (z−u)(z−v)(z−w) and show that u+v+w=−q/r, uv+vw+wu=p/r, and uvw=−1/r.
You may use u+v+w=−q/r and uv+vw+wu=p/r. (i) Show that u2 + v2 + w2 = (q2 − 2pr)/r2. (ii) Hence show that (u − v)2 + (v − w)2 + (w − u)2 = 2(q2 − 3pr)/r2.
Consider Fc(x) = x3 + cx2 − 6x + 1, where c is real. You may use the sufficient condition: a real cubic x³+px²+qx+r, r≠0, has a nonreal root if q²<3pr. Show that F₁₃(x)=0 has a nonreal root.
A real quartic x4 + px3 + qx2 + rx + s = 0, s≠0, has nonzero roots α,β,γ,δ. Their reciprocals u,v,w,z satisfy u+v+w+z=−r/s and uv+uw+uz+vw+vz+wz=q/s. (i) Express u²+v²+w²+z² in terms of q,r,s. (ii) Hence state a sufficient inequality in q,r,s for the original…
A real quartic with coefficients q,r,s as in x⁴+px³+qx²+rx+s has a nonreal root whenever r²<2qs. Use this to show that x4 + 2x3 + 4x2 − 3x + 2 = 0 has a nonreal root.
Consider x4 + 8x3 − 15x2 − 9x − 2 = 0, which has exactly one integer root. You may use two sufficient criteria: a quartic x⁴+px³+qx²+rx+s has a nonreal root if r²<2qs; a cubic x³+px²+qx+r, r≠0, has one if q²<3pr. (i) State what the quartic criterion tells you here.…
Express the product of its roots in terms of k.
Determine k for which one root is positive and the other negative.
For this 120° configuration, suppose z₁,z₂ are the distinct roots of z2 + az + b = 0 with real a,b. Use z12 + z22 = −z1z2 to show that a²−b=0.
Now consider z2 + az + 16 = 0. You may use a²=b for the 120° configuration. Deduce that the argument restriction 0<α−θ<π permits only one such triangle.
Use the product of the four roots to find a.
Find p.
Suppose x2 − 3x + 2 is a factor of P. (i) Express b in terms of a. (ii) Hence show that a=5,b=8,c=4 is the only permitted assignment. (iii) Factor P completely into linear factors. (iv) Sketch y=P(x), labelling all intercepts.
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