Chemistry HL Paper 1A, May 2025, TZ2

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IB, sylabus 2023 (egzaminy od 2025) | 40 zad. w bazie

Zadanie 1Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

A beaker contains a clear, colourless solution of potassium nitrate in water. What is the type of mixture and the best method of obtaining the solid salt from it? A. heterogeneous, by filtration B. heterogeneous, by evaporation C. homogeneous, by filtration D.…

Zadanie 5Paper 1A, maj 2025, TZ2
wzorowane1 pktzamknięteśrednie (szac.)

What is the empirical formula of a compound with the following composition by mass? Element C H O Percentage by mass 54.5 % 9.1 % 36.4 % A. CX6HOX4\ce{C6HO4} B. CX4HX8O\ce{C4H8O} C. CX2HX4O\ce{C2H4O} D. CX4HX8OX2\ce{C4H8O2}

Zadanie 10Paper 1A, maj 2025, TZ2
wzorowane1 pktzamknięteśrednie (szac.)

Methanoic acid, HCOOH\ce{HCOOH}, has the structure shown. What are the hybridizations of the carbon atom, the oxygen atom of the C=O bond and the oxygen atom of the O–H bond? In each option the hybridizations are listed in that order. A. sp2\mathrm{sp^2},…

Zadanie 11Paper 1A, maj 2025, TZ2
wzorowane1 pktzamknięteśrednie (szac.)

Which monomer produces this addition polymer? A. CHX2=CHCHX2CHX3\ce{CH2=CHCH2CH3} B. CHX3CH=CHCHX3\ce{CH3CH=CHCH3} C. CHX2=C(CHX3)X2\ce{CH2=C(CH3)2} D. CHX2=CHCH=CHX2\ce{CH2=CHCH=CH2}

Zadanie 21Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

Which change results in a decrease in entropy? A. 2NaHCOX3(s)NaX2COX3(s)+HX2O(g)+COX2(g)\ce{2NaHCO3(s) -> Na2CO3(s) + H2O(g) + CO2(g)} B. IX2(s)IX2(g)\ce{I2(s) -> I2(g)} C. CO(g)+2HX2(g)CHX3OH(l)\ce{CO(g) + 2H2(g) -> CH3OH(l)} D. KNOX3(s)KNOX3(aq)\ce{KNO3(s) -> KNO3(aq)}

Zadanie 23Paper 1A, maj 2025, TZ2
wzorowane1 pktzamknięteśrednie (szac.)

What are the limiting reactant and the theoretical yield of hydrogen when 0.30 mol of aluminium reacts with 0.60 mol of hydrochloric acid? 2Al(s)+6HCl(aq)2AlClX3(aq)+3HX2(g)\ce{2Al(s) + 6HCl(aq) -> 2AlCl3(aq) + 3H2(g)} In each option the limiting reactant is given first and the theoretical…

Zadanie 25Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

Which changes increase the rate of the reaction? CaCOX3(s)+2HCl(aq)CaClX2(aq)+HX2O(l)+COX2(g)\ce{CaCO3(s) + 2HCl(aq) -> CaCl2(aq) + H2O(l) + CO2(g)} I. Grinding the calcium carbonate into a fine powder II. Using a larger volume of hydrochloric acid of the same concentration III. Warming the…

Zadanie 26Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

Which species is an intermediate in the following reaction mechanism? NOX2(g)+NOX2(g)NOX3(g)+NO(g)\ce{NO2(g) + NO2(g) -> NO3(g) + NO(g)} NOX3(g)+CO(g)NOX2(g)+COX2(g)\ce{NO3(g) + CO(g) -> NO2(g) + CO2(g)} A. NOX2\ce{NO2} B. NOX3\ce{NO3} C. NO\ce{NO} D. COX2\ce{CO2}

Zadanie 27Paper 1A, maj 2025, TZ2
wzorowane1 pktzamknięteśrednie (szac.)

The rate of the reaction between propanone and iodine in acidic solution was measured at a fixed concentration of the acid catalyst. CHX3COCHX3(aq)+IX2(aq)CHX3COCHX2I(aq)+HI(aq)\ce{CH3COCH3(aq) + I2(aq) -> CH3COCH2I(aq) + HI(aq)} [CHX3COCHX3][\ce{CH3COCH3}] / moldm3\mathrm{mol\,dm^{-3}} [IX2][\ce{I2}] /…

Zadanie 28Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

Which statement about the rate constant, k, of an elementary reaction is correct? A. k increases when the temperature is raised, whether the reaction is exothermic or endothermic. B. k decreases when the temperature is raised for exothermic reactions. C. k…

Zadanie 29Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

The following system is at equilibrium. HX2(g)+IX2(g)2HI(g)\ce{H2(g) + I2(g) <=> 2HI(g)} K=54K = 54 What is the value of the equilibrium constant, K, for the reaction 2HI(g)HX2(g)+IX2(g)\ce{2HI(g) <=> H2(g) + I2(g)}? A. 54-54 B. 154\dfrac{1}{54} C. 54\sqrt{54} D. 154\dfrac{1}{\sqrt{54}}

Zadanie 31Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

What is the conjugate acid of the hydrogen phosphate ion, HPOX4X2\ce{HPO4^2-}? A. POX4X3\ce{PO4^3-} B. HX2POX4X\ce{H2PO4-} C. HX3POX4\ce{H3PO4} D. HPOX3X2\ce{HPO3^2-}

Zadanie 32Paper 1A, maj 2025, TZ2
wzorowane1 pktzamknięteśrednie (szac.)

Which solution has a pH of 11.0 at 298 K? A. 103 moldm310^{-3}\ \mathrm{mol\,dm^{-3}} KOH(aq)\ce{KOH(aq)} B. 1011 moldm310^{-11}\ \mathrm{mol\,dm^{-3}} KOH(aq)\ce{KOH(aq)} C. 103 moldm310^{-3}\ \mathrm{mol\,dm^{-3}} NHX3(aq)\ce{NH3(aq)} D. 103 moldm310^{-3}\ \mathrm{mol\,dm^{-3}} HCl(aq)\ce{HCl(aq)}

Zadanie 33Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

What is the main reason why nitric acid has a lower pH than ethanoic acid of the same concentration? A. Nitric acid is an oxidizing agent. B. Nitric acid ionizes to a greater extent in water. C. The conjugate base of nitric acid is stronger than that of…

Zadanie 37Paper 1A, maj 2025, TZ2
wzorowane1 pktzamknięteśrednie (szac.)

What is the standard cell potential, EcellE^\ominus_\text{cell}, of the following cell? PbX2+(aq)+2eXPb(s)\ce{Pb^2+(aq) + 2e- <=> Pb(s)} E=0.13 VE^\ominus = -0.13\ \mathrm{V} ZnX2+(aq)+2eXZn(s)\ce{Zn^2+(aq) + 2e- <=> Zn(s)} E=0.76 VE^\ominus = -0.76\ \mathrm{V} A. 0.89 V-0.89\ \mathrm{V} B. 0.63 V-0.63\ \mathrm{V}

Zadanie 38Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

Which change represents oxidation of the functional group? A. CHX3COCHX3CHX3CH(OH)CHX3\ce{CH3COCH3 -> CH3CH(OH)CH3} B. CHX3CH(OH)CHX3CHX3COCHX3\ce{CH3CH(OH)CH3 -> CH3COCH3} C. CHX3CHX2COOHCHX3CHX2CHO\ce{CH3CH2COOH -> CH3CH2CHO} D. CHX3CH=CHX2CHX3CHX2CHX3\ce{CH3CH=CH2 -> CH3CH2CH3}

Zadanie 39Paper 1A, maj 2025, TZ2
wzorowane1 pktzamknięteśrednie (szac.)

What are the products of the electrolysis of concentrated aqueous sodium chloride using inert electrodes? In each option the product at the anode is given first and the product at the cathode second. A. chlorine gas, hydrogen gas B. chlorine gas, sodium metal…

Zadanie 40Paper 1A, maj 2025, TZ2
wzorowane1 pktzamkniętełatwe (szac.)

Which equation represents a propagation step in the radical substitution of ethane by bromine? A. BrX22Br\ce{Br2 -> 2Br•} B. CX2HX5+BrCX2HX5Br\ce{•C2H5 + Br• -> C2H5Br} C. CX2HX6+BrCX2HX5Br+H\ce{C2H6 + Br• -> C2H5Br + H•} D. CX2HX5+BrX2CX2HX5Br+Br\ce{•C2H5 + Br2 -> C2H5Br + Br•}